1

a

In de onderste rij komt van links naar rechts: $25 15 10$ $15 9 6$ $10 6 4$ .

b

$0,06$

c

$0,25$

d

$0,38$

2

a

$12$ , $15$

b

$0,3 \cdot 0,2$

c

$0,5 \cdot 0,2 = 0,1$

3

$\frac{3}{4} \cdot \frac{3}{4} \cdot \frac{3}{4} = \frac{27}{64}$

4

a

Sharon moet drie keer succes hebben, de kans daarop is $0,4 \cdot 0,4 \cdot 0,4 = 0,064$ .

b

Mark moet drie keer geen succes hebben, de kans daarop is $0,6 \cdot 0,6 \cdot 0,6 = 0,216$ .

5

a

$\frac{4}{9}$ , $\frac{5}{9}$

b

c

$\frac{3}{10} \cdot \frac{2}{9} = \frac{1}{15}$

d

Dan pakt ze gg, gb, bg of bb, de kans daarop is: $\frac{3}{10} \cdot \frac{2}{9} + \frac{3}{10} \cdot \frac{2}{9} + \frac{2}{10} \cdot \frac{3}{9} + \frac{2}{10} \cdot \frac{1}{9} = \frac{18}{90} = \frac{2}{9}$ .

e

$\frac{5}{10} \cdot \frac{4}{9} + \frac{3}{10} \cdot \frac{2}{9} + \frac{2}{10} \cdot \frac{1}{9} = \frac{28}{90} = \frac{14}{45}$

6

a

b

$\frac{3}{5} \cdot \frac{3}{5} \cdot \frac{2}{5} = \frac{18}{125}$

c

$\frac{2}{5} \cdot \frac{2}{5} \cdot \frac{3}{5} + \frac{3}{5} \cdot \frac{2}{5} \cdot \frac{2}{5} + \frac{2}{5} \cdot \frac{3}{5} \cdot \frac{2}{5} = \frac{36}{125}$

7

a

b

$\frac{3}{5} \cdot \frac{2}{4} \cdot \frac{2}{3} = \frac{12}{60} = \frac{1}{5}$

c

$\frac{2}{5} \cdot \frac{1}{4} \cdot 1 + \frac{2}{5} \cdot \frac{3}{4} \cdot \frac{1}{3} + \frac{3}{5} \cdot \frac{2}{4} \cdot \frac{1}{3} = \frac{3}{10}$

8

a

Zie de figuur links

b

$\frac{7}{42} \cdot \frac{35}{42} \cdot \frac{35}{42} \cdot 3 = \frac{75}{216} \approx 0,35$

c

Zie de figuur rechts.

9

a

kansboom bij 46

b

$\frac{2}{3} \cdot \frac{3}{5} = \frac{2}{5}$

c

$1 - \frac{2}{5} = \frac{3}{5}$

10

a

kansboom bij 47

${(\frac{1}{3})}^{3} = \frac{1}{27}$

b

$\frac{1}{3} \cdot \frac{2}{3} \cdot \frac{2}{3} + \frac{2}{3} \cdot \frac{1}{3} \cdot \frac{2}{3} + \frac{2}{3} \cdot \frac{2}{3} \cdot \frac{1}{3} = \frac{12}{27} = \frac{4}{9}$

11

a

Zonder terugleggen.

kansboom bij 48

b

$\frac{5}{7} \cdot \frac{4}{6} \cdot \frac{3}{5} = \frac{2}{7}$

c

$1 - \frac{2}{7} = \frac{5}{7}$